The function f satisfies
f(sqrt(x+1)
for all x>=-1, x isn't equal to 0. Find f(2).
+118609 The function f satisfies
f(sqrt(x+1)
for all x>=-1, x isn't equal to 0. Find f(2).
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This notation looks odd to me. There is a bracket messing but even with that it does not make a lot of sense to me.
Could you check it please?
All I can say is that if you want f(sqrt(x+1)) and sqrt(x+1)=2 then
\(\sqrt{x+1}=2\\ x+1=4\\ x=3\)
I cannot find f(2) becasue the function is not defined. There are no equal signs.
