A distributor has two gasohol blends: one that contains 5.00% alcohol and another with 11.0% alcohol. How many litres of each must be mixed to make 412 L of gasohol containing 9.50% alcohol
+36916 sum of ingredients = final ingredients
x = 5 % amount
(412-x) = 11% amount
.05 x + .11 ( 412-x) = .095 (412 ) solve for 5% amount, x....then 11% amount = 412-x
