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A distributor has two gasohol blends: one that contains 5.00% alcohol and another with 11.0% alcohol. How many litres of each must be mixed to make 412 L of gasohol containing 9.50% alcohol

 Mar 16, 2020
 #1
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sum of ingredients = final ingredients

x = 5 % amount  

(412-x) = 11% amount

 

.05 x       +  .11 ( 412-x)          =    .095 (412 )        solve for 5% amount, x....then 11% amount  =    412-x

 Mar 16, 2020

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