The circle 2x^2 = -2y^2 + 12x - 4y + 20 is inscribed inside a square which has a pair of sides parallel to the x-axis. What is the area of the square?
+37146 Find the radius of the circle..... then the sqaure has sides = 2 * r and you can calculate the area
2x^2 = -2y^2 + 12x - 4y + 20
2x^2 - 12x + 2y^2 + 4y = 20
x^2 - 6x + y^2 + 2y = 10
(x-3)^2 + (y-1)^2 = 10 + 9 + 1 20 = r^2 of the circle
Square 2*r x 2*r = 4 r^2 4(20) = 80 units2
