Erik took a trip to see his friend Mike who lives 308 miles away. He left his place at 10 AM driving at 70 mph. In 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph. At what time will they meet?
By the time Mike left his house at 12:00 noon, Erik had already traveled: 2 x 70 mph =140 miles.
308 - 140 = 168 miles left.
Let the time when they meet =T
70T + 50T =168 miles, solve for T
T =7 / 5 =1.4 hours, or 1 hour and 24 minutes after 12:00 noon.
12 + 1.4 =1 O'clock + 24 minutes, or 24 minutes after 1:00 pm when they will meet.
By the time Mike left his house at 12:00 noon, Erik had already traveled: 2 x 70 mph =140 miles.
308 - 140 = 168 miles left.
Let the time when they meet =T
70T + 50T =168 miles, solve for T
T =7 / 5 =1.4 hours, or 1 hour and 24 minutes after 12:00 noon.
12 + 1.4 =1 O'clock + 24 minutes, or 24 minutes after 1:00 pm when they will meet.
