How many real solutions are there to the equation √x+5= |2x|? (Note: Both x and 5 are under the same square root symbol)
Note that l2xl = sqrt [ (2x)^2 ]
So
sqrt [x + 5] = sqrt [ (2x)^2] which implies that
x + 5 = (2x)^2
x + 5 = 4x^2
4x^2 - x - 5 = 0
(4x - 5) ( x + 1) = 0
4x - 5 = 0 x + 1 = 0
x = 5/4 x = -1
