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Graph the inequality -3x + 3y >= -12.

 

 Apr 20, 2020
 #1
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Let's first get this into a normal equation "y = mx + b" form.

 

-3x + 3y >= 12

3y >= 3x + 12 

y >= x + 4


From this, we can find the x and y intercepts to make it easier to graph. After plugging in 0 for x and y, we get the two intercepts....

 

x - intercept: (0, -4)

y - intercept: (4, 0)

 

Then, since it is >= and not just >, the line is not dotted, but it is instead shaded in because those are included in the set of values for which y >= x + 4 is valid. Also, since it is >=, you shade above the line. From all of these, I can conclude it is Graph #4.

 Apr 20, 2020

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