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In triangle ABC, BC = 2, AB = 3, angle C = 110 degrees.  Find angle ABC.

 

 Dec 16, 2020
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Use the Law of Sines to first find  angle  A

 

sin A  /2   = sin 110 / 3

 

sin A =  2 sin 110 / 3

 

arcsin   ( 2 sin110  /3)  = A  ≈  38.8°

 

Angle B  = 180  - 110  -  38.8 ≈  31.2°

 

 

cool cool cool

 Dec 16, 2020

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