In triangle ABC, BC = 2, AB = 3, angle C = 110 degrees. Find angle ABC.
Use the Law of Sines to first find angle A
sin A /2 = sin 110 / 3
sin A = 2 sin 110 / 3
arcsin ( 2 sin110 /3) = A ≈ 38.8°
Angle B = 180 - 110 - 38.8 ≈ 31.2°
