Let x^2+bx+c=0 be a quadratic whose roots are each two more than the roots of 3x^2-5x-7. What is c?
By Vieta.....in the last quadratic.....call the roots m ,n
Sum of the roots = m + n = 5/3
Product of the roots = mn = -7/3
And in the first quadratic,
Product of the roots = c
(m+ 2) ( n + 2) = c
mn + 2m + 2n+ 4 = c
-7/3 + 2 ( m + n) + 4 = c
-7/3 + 2 ( 5/3) + 4 =c
-7/3 + 10/3 + 4 = c
1 + 4 = c
5 = c
CORRECTED !!!
Wow, well CPhill even if its wrong that's still really cool that you know how to do that!