Two canoes travel down a river, starting at 10:00. One canoe travels twice as fast as the other. After 3.5 hr, the canoes are 5.25 mi apart. Find the average rate of each canoe.
Let the distance travelled by the faster canoe =D
The distance travelled by the slower canoe =D - 5.25
Let the speed of the slower canoe =S
The speed of the faster canoe =2S
S * 3.5 hours =D - 5.25
2S * 3.5 hours =D, solve for D, S
S =3/2 =1.5 mph - speed of the slower canoe.
1.5 * 2 =3 mph - speed of the faster canoe.
D =21/2 =10.5 miles travelled by the faster canoe.
