+0  
 
0
611
1
avatar

Find a polynomial of degree 3 with real coefficients and zeros of -3,-1, and​ 4, for which ​f(-​2)=-18.

 Apr 9, 2020
 #1
avatar+23245 
0

If a polynomial of degree 3 has zeros at -3, -1, and 4, the polynomial will have this form:

  f(x)  =  a·(x + 3)·(x + 1)·(x - 4)

Since  f(-2)  =  18, we can find the value for a by solving:

   18  =  a·(-2 + 3)·(-2 + 1)·(-2 - 4)

 

Find the value of  a  and substitute this into:

  f(x)  =  a·(x + 3)·(x + 1)·(x - 4)

 Apr 9, 2020

1 Online Users