+0  
 
0
46
1
avatar

Use the identity for tan(A+B) or tan(A-B) to solve each problem {1-6}

1)  tan75° =  tan(30° + 45°)

2)  tan15° = tan(45° + 30°)

3)  tan105° = tan(60° + 45°)

4)  tan195° = tan(135° + 60°)

5)  tan165° = tan(135° + 30°)

6)  tan(-7π/12)= 

 

 

(Formule)

 

https://www.google.com/imgres?imgurl=http%3A%2F%2Fwww.mathguide.com%2Flessons2%2FTrigAngles%2Fsdat11.gif&imgrefurl=http%3A%2F%2Fwww.mathguide.com%2Flessons2%2FSDAT.html&tbnid=uBY8SiVJATahIM&vet=12ahUKEwjX2sqAlavmAhVVMlMKHSuPCmMQMygBegUIARDhAQ..i&docid=Sb_TidArUMQb2M&w=312&h=163&q=sum%20and%20difference%20formulas%20for%20tangent&safe=active&ved=2ahUKEwjX2sqAlavmAhVVMlMKHSuPCmMQMygBegUIARDhAQ&surl=1

 Dec 10, 2019
 #1
avatar
0

tan(a+b)=Tan(a)+Tan(b)/1-Tan(a)Tan(b)

tan(30+45)=tan(30)+tan(45)/1-tan(30)*tan(45)

tan(30)=0.557350269

tan(45)=1

(0.5574+1)/1-0.5574*1=1.5574/0.4426=3.6 approx. 

 Dec 10, 2019

12 Online Users

avatar