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+2
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When the expression \(4(x^2-2x+2)-7(x^3-3x+1)\) is fully simplified, what is the sum of the squares of the coefficients of the terms?

 

How is the answer not 570??? please explain somebody???

Thank you in advance!!!

 Feb 22, 2019
 #1
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+1

4(x^2 - 2x + 2) - 7(x^3 - 3x + 1) =

 

4x^2 -8x + 8   - 7x^3 + 21x -7   =

 

-7x^3  + 4x^2  + 13x  + 1

 

The coeficients are in red  .....  [ "1 "  is a constant term....not a coefficient ]

 

The sum of thier squares are  

 

(-7)^2 + (4)^2 + (13)^2  =

 

49 + 16 + 169 =

 

234

 

 

cool cool cool

 Feb 22, 2019

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