When the expression \(4(x^2-2x+2)-7(x^3-3x+1)\) is fully simplified, what is the sum of the squares of the coefficients of the terms?
How is the answer not 570??? please explain somebody???
Thank you in advance!!!
4(x^2 - 2x + 2) - 7(x^3 - 3x + 1) =
4x^2 -8x + 8 - 7x^3 + 21x -7 =
-7x^3 + 4x^2 + 13x + 1
The coeficients are in red ..... [ "1 " is a constant term....not a coefficient ]
The sum of thier squares are
(-7)^2 + (4)^2 + (13)^2 =
49 + 16 + 169 =
234
