We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
+2
71
1
avatar

When the expression \(4(x^2-2x+2)-7(x^3-3x+1)\) is fully simplified, what is the sum of the squares of the coefficients of the terms?

 

How is the answer not 570??? please explain somebody???

Thank you in advance!!!

 Feb 22, 2019
 #1
avatar+101762 
+1

4(x^2 - 2x + 2) - 7(x^3 - 3x + 1) =

 

4x^2 -8x + 8   - 7x^3 + 21x -7   =

 

-7x^3  + 4x^2  + 13x  + 1

 

The coeficients are in red  .....  [ "1 "  is a constant term....not a coefficient ]

 

The sum of thier squares are  

 

(-7)^2 + (4)^2 + (13)^2  =

 

49 + 16 + 169 =

 

234

 

 

cool cool cool

 Feb 22, 2019

10 Online Users

avatar
avatar