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Circle A has radius 5, and Circle B has radius 2. If CD = 12 and is a common tangent, what is AB?

Jul 13, 2020

#1
+21955
+1

Step 1:  Mark point "X" on AC at the end of the blue line segment.

Step 2:  BX = DC   --->   BX = ...

Step 3:  XC = BD   --->   XC = ...

Step 4:  AX = AC - XC   --->   AX = ...

Step 5: Use the Pythagorean Theorem on triangle(AXB) to find AB ...

Jul 13, 2020
#2
+10395
+1

Circle A has radius 5, and Circle B has radius 2. If CD = 12 and is a common tangent, what is AB?

Hello Guest!

$$\overline {AB}^2=12^2+(5-2)^2\\ =144+9\\ =153\\ \overline{AB}= \sqrt{153}$$

$$\overline{AB}=12.369$$

!

Jul 13, 2020