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katy invests £2000 in a savings account for 3 years. the account pays compound interest at an annual rate of

2.5% for the first year

X% for the second year

X% for the 3rd year

there is a total of £2124.46 in the savings account at the end of 3 years

Work out the rate of interest in the second year

 May 15, 2016
 #1
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What kind of 'compound interest' ???   Continous is what I will assume:

2000e^(.025) = 2050.63 at the beginning of year two

2050.63 e^(r*2) = 2124.46

e^(2r) = 2124.46/2050.63

ln (e^(2r) = ln (2124.46/2050.63)

2r=,03537

r= 1.768 % for years 2 and 3    CONTINOUS COMPOUNDING EXAMPLE

 May 15, 2016
edited by ElectricPavlov  May 15, 2016
 #2
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I will assume a slightly different scenario, since it states that annual interest for the the first year is 2.5% compounded annually: So then we have:

2,000 x 1.025=2,050 balance at the beginning of the 2nd year. But, we have:

2,124.46 / 2,050=1.0363 - 1=.0363 x 100=3.63% interest for the remaining 2 years.

Sqrt(1.0363)=1.80% interest rate for the 2nd and 3rd year. So that:

2,000 x 1.025 x 1.018^2=2,124.46 pounds.

 May 15, 2016

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