+0

+1
40
2

What is the value of this expression?

May 3, 2020

#1
+300
+1

Let's break this up :D

There's $$3a^{-3}$$$$b^2$$$$2a^{-1}$$ and $$b^0$$, where $$a = -2$$ and $$b=-3$$.

$$3a^{-3} = 3((-2)^{-3}) = 3(\frac{1}{(-2)^3}) = \frac{3}{-8} = -\frac{3}{8}$$

$$b^2 = (-3)^2 = 9$$

$$2a^{-1} = 2((-2)^{-1}) = 2(\frac{1}{-2}) = \frac{2}{-2} = -1$$

$$b^0 = 1$$ :D

So, our expression is:

$$(\dfrac{-\frac{3}{8} \cdot 9}{-1 \cdot 1})^2$$

Which is:

$$(\dfrac{-\frac{27}{8}}{-1})^2$$

Which makes:

$$(\frac{27}{8})^2$$

Which equals:

$$\fbox{\frac{729}{64}}$$

Which is the last option :D

May 3, 2020
#2
+657
+1

Great job showing your steps! Keep it up CentsLord!!!

LuckyDucky  May 3, 2020