+0

+1
97
2
+2297

Solve the system of equations by elimination.

Sep 3, 2018

#1
+2297
0

No solution?

Sep 3, 2018
#2
+20831
+6

Solve the system of equations by elimination:

$$\begin{array}{|lrcll|} \hline (1) & 4x + 8y &=& -16 \quad & | \quad -8y \\ & 4x &=& -16 -8y \\\\ (2) & -8x + 10y &=& -20 \\ & -2\cdot (4x) + 10y &=& -20 \quad & | \quad 4x = -16 -8y \\ & -2\cdot ( -16 -8y) + 10y &=& -20 \\ & 32 + 16y + 10y &=& -20 \\ & 32 + 26y &=& -20 \quad & | \quad -32 \\ & 26y &=& -20-32 \\ & 26y &=& -52 \quad & | \quad : 26 \\ & y &=& -\frac{52}{26} \\ & \mathbf{y} & \mathbf{=} & \mathbf{-2} \\\\ & 4x &=& -16 -8y \quad & | \quad :4 \\ & x &=& -4 -2y \quad & | \quad \mathbf{y = -2} \\ & x &=& -4 -2\cdot (-2) \\ & x &=& -4 +4 \\ & \mathbf{x} & \mathbf{=} & \mathbf{0} \\ \hline \end{array}$$

Sep 4, 2018