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avatar+2297 

Solve the system of equations by elimination.

 Sep 3, 2018
 #1
avatar+2297 
0

No solution?

 Sep 3, 2018
 #2
avatar+20831 
+6

Please help!

Solve the system of equations by elimination:

 

\(\begin{array}{|lrcll|} \hline (1) & 4x + 8y &=& -16 \quad & | \quad -8y \\ & 4x &=& -16 -8y \\\\ (2) & -8x + 10y &=& -20 \\ & -2\cdot (4x) + 10y &=& -20 \quad & | \quad 4x = -16 -8y \\ & -2\cdot ( -16 -8y) + 10y &=& -20 \\ & 32 + 16y + 10y &=& -20 \\ & 32 + 26y &=& -20 \quad & | \quad -32 \\ & 26y &=& -20-32 \\ & 26y &=& -52 \quad & | \quad : 26 \\ & y &=& -\frac{52}{26} \\ & \mathbf{y} & \mathbf{=} & \mathbf{-2} \\\\ & 4x &=& -16 -8y \quad & | \quad :4 \\ & x &=& -4 -2y \quad & | \quad \mathbf{y = -2} \\ & x &=& -4 -2\cdot (-2) \\ & x &=& -4 +4 \\ & \mathbf{x} & \mathbf{=} & \mathbf{0} \\ \hline \end{array}\)

 

laugh

 Sep 4, 2018

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