We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
143
1
avatar

If \(\frac{3x^2-4x+1}{x-1}=m\), and x can be any real number except 1, what real values can m NOT have?

 Aug 1, 2019
 #1
avatar+6045 
+1

\(f(x) = \dfrac{3x^2-4x+1}{x-1}=\\ \dfrac{(3x-1 )(x-1 )}{x-1}=3x-1\\ \text{but with a "hole" at $x=1$ so $3(1)-1=2$ is not in the range of $f(x)$}\)

 

\(\text{$x = 1$ is known as a removable singularity}\)

.
 Aug 1, 2019
edited by Rom  Aug 1, 2019

12 Online Users

avatar
avatar
avatar