The equation of a parabola is given. y=3/4x^2−6x+15 What are the coordinates of the vertex of the parabola?
The 'x' coordiante of the parabola will be - b / 2a = - -6/(2*3/4) use this value in the quadratic to calculate the 'y' coordinate of the vertex.
I don't get it, -6/1 is still -6? or am I missing something here?