+99 The standard form of the equation of a circle is (x−3)2+(y−1)2=16.
What is the general form of the equation?
x2+y2−6x−2y−6=0
x2+y2+6x+2y+26=0
x2+y2−6x−2y−26=0
x2+y2+6x+2y−6=0
+9479 (x - 3)2 + (y - 1)2 = 16
To get this into general form, we need to multiply out (x - 3)2 and (y - 1)2 .
(x - 3)(x - 3) + (y - 1)(y - 1) = 16 First, let's just do (x - 3)2 .
x2 - 3x - 3x + 9 + (y - 1)(y - 1) = 16 Now, let's do (y - 1)2 .
x2 - 3x - 3x + 9 + y2 - 1y - 1y + 1 = 16 Subtract 16 from both sides of the equation.
x2 - 3x - 3x + 9 + y2 - 1y - 1y + 1 - 16 = 0 Combine like terms.
x2 - 6x + y2 - 2y - 6 = 0 Rearrange.
x2 + y2 - 6x - 2y - 6 = 0
