What is an equation of a line parallel to y = 3x + 2, passing through (-4, 1).
well we know that the equation of a line parallel to the given line must retain the same slope. As such, the slope has to be 3 as well. We can then write part of the equation of the line as
y = 3x + b
Now we just solve for b, by plugging in the point (-4, 1) which we know the line passes through. With this point, we get 1 = -12 + b. Adding 12 on both sides, we get 13 = b.
We then get the equation:
y = 3x + 13