A vertical pole AB measuring 5 meters snaps at point C. The pole remains in contact at C and the top of the pole touches the ground at point T, a distance of 3 meters from A.
Find the length AC, in meters, the point where the pole snapped.
+36916 The broken pole forms a RIGHT triangle with the ground
the slanted portion we will cal 'h' (as in 'hypotenuse' )
the vertical portion is 5 - h
and the other leg of the triangle (the ground ) = 3
(5-h)^2 + 3^2 = h^2
h^2 -10h+25+9 = h^2
-10h = -34
h = 3.4 the pole broke 3.4 meters from the top .... AC is thus: 5-3.4 = 1.6 meters
