#1**+2 **

There isn't anything to solve.....we just want to evaluate this : tan (acos(3/x))

Let acos(3/x) = theta

So.....theta is an angle whose cosine = 3 / x

So.... using the Pythagorean Theorem......y = sqrt (x^2 - 3^2) = sqrt (x^2 - 9)

So..... tan (acos(3/x)) = tan (theta) = y / x = sqrt (x^2 - 9) / 3

CPhill Jan 14, 2019