#1**+3 **

The circle has area 64pi and that means angle AOB is 60 degrees since it's equalateral so we have 32pi/3 for the sector and for the triangle is 8*4sqrt3=32sqrt3 we then divide by 2 to get 16sqrt3 we subtract to get **32pi/3-16sqrt3 so we have \(\boxed{(B)\dfrac{32\pi}3-16\sqrt3}\)**

jimkey17 Aug 6, 2020

#2**+1 **

Angle o is 60 degrees (equilateral triangle)

60 / 360 x pi x 8^2 - 8^2 sqrt3/4 red is area of equilateral triangle

ElectricPavlov Aug 6, 2020