Let n be a positive integer.

When n is divided by 2, the remainder is 1.

When n is divided by 3, the remainder is 2.

When n is divided by 4, the remainder is 3.

When n is divided by 5, the remainder is 4.

When n is divided by 6, the remainder is 5.

What is the smallest possible value of n?

Guest May 11, 2020

#1**0 **

When n is divided by 2, the remainder is 1.

When n is divided by 3, the remainder is 2.

When n is divided by 4, the remainder is 3.

When n is divided by 5, the remainder is 4.

When n is divided by 6, the remainder is 5.

LCM[2, 3, 4, 5, 6] = 60

n =60m + 59, where m =0, 1, 2, 3, 4......etc.

So, the smallest n = 59.

Guest May 11, 2020