Amber has 19 coins that are dimes and quarters. If they are worth $3.70 then how many dimes and quarters does she have?
Let
x= dimes
y= quarters
x+y=19
10x+25y=370
Use elimination....
10x+10y=190
10x+25y=370 (subtract both equations)
-15y=-180
y=12
So, there are 12 quarters and 7 dimes.
d = dimes value 10 d
q = quarters = 19-d value 25 (19-d) summed = 370
10d + 25(19-d) = 370 solve for d , the number of dimes then #q = 19-d