please help!

Let the distance from Post Office to Friend's house =D

7/8 + 5/6 + D =miles - Total distance from Georgia's house to a Friend's house.

42 minutes / 18 minutes per mile =2 1/3 miles - toal distance from her house to a friend's house. So, we have:

7/8 + 5/6 + D = 2 1/3, solve for D

[21 + 20] / 24 + D = 2 1/3

41/24 + D = 2 1/3                     subtract 41/24 from both sides

D =2 1/3 - 41/24

D =7/3 - 41/24

D =[56 -41] / 24

D = 15 / 24

D = 5/8 of a mile - distance between the Post Office and her Friend's house.

Is your question missing something?

yes it is, sorry the asy did not load:

To get from her home to a friend's house, Georgia must go past a school, then a post office:

home---school---post office---freind's house

Signs tell Georgia that the distance she walks from home to the school is  mile, and the distance from the school to the post office is  mile.

The whole trip takes Georgia  minutes. If Georgia can walk a mile in  minutes, then how many miles is the distance from the post office to her friend's house?

You are still missing NUMBERS from your question. Type them by hand into your question.

SO SORRY 

To get from her home to a friend's house, Georgia must go past a school, then a post office:

home---school---post office---freind's house

Signs tell Georgia that the distance she walks from home to the school is 7/8 mile, and the distance from the school to the post office is 5/6 mile.

The whole trip takes Georgia 42 minutes. If Georgia can walk a mile in 18 minutes, then how many miles is the distance from the post office to her friend's house?

THANK YOU SOOO MUCH!!!