Please Help!

There may be a better way but I started by expanding it all out and simplify

Taking it to one side and put equal to 0

After you do that and present your answer here I will help you more.

n³= n³-1+n³-8+n³-27

n³=n³+n³+n³-1-8-27

n³=3n³-9-27

n³=3n³-18

-n³+n³=-18/3

6 (ans)

Expanding a little bit on Melody's answer...

You expand and get $n^3 = (n^3-3n^2-3n+1)+(n^3-6n^2+12n+8)+(n^3-9n^2+27n-27)$.

Solve from here.