\(\frac{|x-2|}{|x+3|}<7\)
1) For starters x cannot equal -3. Why is that?
2) If x=2 then is it true? Why?
3) So I need to look at 3 regions. Where x is less than -3, where x is between -3 and 2, and lastly where x is bigger than 2.
When x<-3,
x-2 is negative and x+3 is also neg so this means
|x-2| = -(x-2)=2-x
|x+3|=-(x+3)| = -x-3
See if you can continue from here.
If you get stuck then, display what you have done, and I will help further.
Please no one do any more unless the asker displays a concerted effort first.
\frac{|x-2|}{|x+3|}<7