#1**+1 **

\(\frac{|x-2|}{|x+3|}<7\)

1) For starters x cannot equal -3. Why is that?

2) If x=2 then is it true? Why?

3) So I need to look at 3 regions. Where x is less than -3, where x is between -3 and 2, and lastly where x is bigger than 2.

When x<-3,

x-2 is negative and x+3 is also neg so this means

|x-2| = -(x-2)=2-x

|x+3|=-(x+3)| = -x-3

See if you can continue from here.

If you get stuck then, display what you have done, and I will help further.

**Please no one do any more unless the asker displays a concerted effort first.**

\frac{|x-2|}{|x+3|}<7

Melody May 23, 2020