Let F=log1+x1−x
Express G=log(1+3x+x31+3x21−3x+x31+3x2) in terms of F.
G = log(1+3x+x31+3x21−3x+x31+3x2) G = log(1+3x21+3x2+3x+x31+3x21+3x21+3x2−3x+x31+3x2) G = log(x3+3x2+3x+11+3x2−x3+3x2−3x+11+3x2) G = log(x3+3x2+3x+1−x3+3x2−3x+1) G = log((1+x)3(1−x)3) G = log((1+x1−x)3) G = 3log(1+x1−x) G = 3F .
Impressive, hectictar !!!!