+0  
 
0
36
3
avatar

please help 

 

http://prntscr.com/m7ze53

 Jan 16, 2019
 #1
avatar+96439 
+1

Here is the graph :  http://prntscr.com/m7ze53

 

 

cool cool cool

 Jan 16, 2019
 #3
avatar+96439 
+1

Sorry....

 

Here is the image :

 

https://www.desmos.com/calculator/vftm09zss4

 

The midline is 

 

[ Highest point on graph - Lowest point on graph] / 2   = y =   [ 6 + - 2 ] / 2  =  4 / 2  =  2

 

So    y  = 2

 

The first max point is  (pi /6, 6 )

 

cool cool cool

CPhill  Jan 16, 2019
 #2
avatar
0

lol thats the same link as my question 

 

also i just need help on where to put the midline and max

 Jan 16, 2019

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