Write the slope-intercept form of the equation of the line with that passes through the point (5,4) and is parallel to 3x+4y=12 .
+230 We first turn 3x+4y=12 into standard form:
4y=-3x+12
y=-3/4x+3
By knowing the 2nd line is parrelell to the first, the slopes are the same:
y=-3/4x+b
Plugging in (5,4) into the equation:
4=-15/4+b
b=1/4
Final equation=y=-3/4+1/4.
