There is a 6x8 rectangle with a circle wrapped around it. You need to find the area of the part of circle not covered by the rectangle.
+130516 Using the Pythagorean Theorem, we can find the length of the diagonal(s) of the rectangle:
Diagonal length = sqrt(6^2 + 8^2) = sqrt (100) = 10
The circle's center will lie at the intersection of these diagonals and its radius will be (1/2) the length of a diagonal = 5
So.....the area of the circle - the area of the rectangle = the part of the circle lying outside the rectangle ....
pi*(radius)^2 - Length of rectangle * width of rectangle =
pi (5)^2 - 6*8 =
25pi - 48 = about 30.54 units^2
