If x, y, and z are positive integers such that 6xyz+30xy+21xz+2yz+105x+10y+7z=812, find x+y+z.

Guest Dec 27, 2018

#2**+1 **

Maybe some method to solve this, but I certainly do not know what it might be....

WolframAlpha gives (x, y, z) = (2, 2, 6)

CPhill Dec 27, 2018