If (2, -7) and (8, 15) are the endpoints of a diameter of a circle, what is the equation of the circle?
+36915 Find the distance between these points....this will be the diameter
sqrt ((2-8)^2 + (-7-15)^2) = sqrt (36 + 484) = sqrt 520 1/2 of this is the RADIUS = sqrt 520 / 2
the CENTER (h,k) of the circle is the midpoint between the given points h,k = 5, 4
Circle equation = (x-h)^2 + (y-k)^2 = r^2
(x-5)^2 + ( y-4)^2 = 520/4 = 130
