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A student divided  \(f(x) = 3x^3+8x^2+5x-4\)  by \(x+2\)  and found the remainder was \(r=-6\). Based on the remainder theorem, what can be concluded about \(f(x)\)?

 

a) The point \((-2,-6)\) lies on the graph of  \(f(x)\).

 

b) The function \(f(x)=3x^3+8x^2+5x-4\)  has a zero at \(-6\)

 

c) The function \(f(x)=3x^3+8x^2+5x-4\) has a zero at \(-2\)

 

d) The y-intercept of the graph of \(f(x)\) is \(-6\).

 
 May 1, 2021
 #1
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The answer is A 

x-4=-6,

x=-2 

 

 

 

:)

 
 May 1, 2021

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