+0  
 
0
85
6
avatar

Please help with this question!!!!

 Apr 11, 2022
 #1
avatar
0

ABC is a 3 4 5   right triangle     area = 1/2  3 * 4   units2

 

DEF is also a right triangle ....since arcos D = 3/5     EF = 3      so the area is the same as the first one !

 Apr 11, 2022
 #2
avatar
0

But the thing is none of these are right angles...

 

Please help!!!!!!!!!!!!!!!!

Guest Apr 11, 2022
 #3
avatar
0

Use cos law to find   CB

  then use Heron's rule to find the area of triangle ABC

 

Similar for   DEF    use cos law to find    EF    then heron's rule to find area

 Apr 11, 2022
 #4
avatar
0

   Agree with Guest.....   this answer is incorrect.....(see better answer further down)

 Apr 11, 2022
 #5
avatar
0

Yea I don't understand how to even approach this.....

 

I need help too

 Apr 11, 2022
 #6
avatar
0

Use cos law to find   CB

  then use Heron's rule to find the area of triangle ABC

 

Similar for   DEF    use cos law to find    EF    then heron's rule to find area

Heron's Rule:

 

Area of triangle ABC = √s(s-a)(s-b)(s-c), where s = Perimeter/2 = (a + b + c)/2

Guest Apr 11, 2022

31 Online Users

avatar