3√6x-12 + 4 =12
Thanks
Hello Guest!
I guess
\(\sqrt[3]{6x-12}+4=12\ |-4\\ \sqrt[3]{6x-12}=12-4\ |\ ^3\\ 6x-12=8^3\ |\ +12\\ 6x=512+12\ |\ :6\\ \color{blue}x=87.\overline 3\)
Hi Guest,
hi asinus,
Maybe he is just meaning that:
\(\sqrt[3]{6x}-12+4=12\)
Then would be the solution:
\(\approx {\frac{4000}{3}} \mbox { (wolframalpha)}\)
Straight
