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What is the equation of a line perpendicular to y=4x-5 that passes through (8,1)?

Guest Feb 25, 2017
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\(y_1=m_1 x + b_1\)

is perpendicular to

\(y_2=m_2 x + b_2\)

if \(m_1 m_2 = -1\)

(see https://www.mathsisfun.com/algebra/line-parallel-perpendicular.html for more information)

 

\(m_1 = 4 \\ m_2 = -1/4\)

 

Given that the line should passes through (8,1), we get \(b_2\):

\(1=-1/4*8+b_2 \\ b_2 = 3\)

 

So, the answer is: \(y=-1/4 x + 3\)

Guest Feb 25, 2017

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