We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
113
1
avatar

please help I know that the first part is 2 but please need the second part quickly thanks you.

 May 21, 2019
 #1
avatar+105195 
+3

Using the Law of Sines,we have

 

sin (pi/6)/ (3 x)  = sin B / x

 

(1/2) / 3   =   sin B

 

sin B  = (1/6)

 

So    12sin B  =  12 (1/6)  =   2

 

 

C  = pi - A - B

 

C = pi - pi/6 - arcsin (1/6)

 

C = 5pi/6 - arcsin(1/6)

 

sin C  =  sin (5pi/6 - arcsin (1/6) )    =  sin (A - B)  =  sinAcosB - sin B cos A

 

sin C  =   (1/2)sqrt(35)/6 -  (1/6)(-sqrt(3)/2)

 

sin C  =[  sqrt (35) +sqrt(3)] / 12

 

So

 

12 sin C    =    12  [ sqrt(35) + sqrt(3) ] / 12  =     [ sqrt(35) + sqrt(3) ]

 

 

cool cool cool

 May 22, 2019

30 Online Users

avatar
avatar
avatar