please help I know that the first part is 2 but please need the second part quickly thanks you.
+128475 Using the Law of Sines,we have
sin (pi/6)/ (3 x) = sin B / x
(1/2) / 3 = sin B
sin B = (1/6)
So 12sin B = 12 (1/6) = 2
C = pi - A - B
C = pi - pi/6 - arcsin (1/6)
C = 5pi/6 - arcsin(1/6)
sin C = sin (5pi/6 - arcsin (1/6) ) = sin (A - B) = sinAcosB - sin B cos A
sin C = (1/2)sqrt(35)/6 - (1/6)(-sqrt(3)/2)
sin C =[ sqrt (35) +sqrt(3)] / 12
So
12 sin C = 12 [ sqrt(35) + sqrt(3) ] / 12 = [ sqrt(35) + sqrt(3) ]
