+26367 I dont understand how to do this. Please show steps
EC=
\(\text{Let $ES=ER=30$} \\ \text{Let $DT=DR=17$} \\ \text{Let $TC=SC=32$} \\ \text{Let the perimeter is $c+d+e$} \)
\(\begin{array}{|rcll|} \hline c+d+e &=& 2*17+2*30+2*32 \\ \mathbf{c+d+e} &=& \mathbf{158} \\ \hline \end{array}\)
The perimeter of \(\triangle DEC\) is \(\mathbf{158}\)
