Find the measure of angle j, the smallest angle in a triangle with sides measuring 11,13 and 19. Round the the nearest whole degree
+36916 Use law of cosines
c2 = a2 + b2 − 2ab cos(C)
C = Arccos ((a² + b² - c²) / 2ab)
smallest angle (C) will be across from side 11
C = arcos( (19^2+ 13^2 - 11^2)/2(13)(19) 0 = 34.11 = ~~34 degreesdegrees
