Find the number of integers x satisfying \(\sqrt[3]{24 + x} + \sqrt{12 - x} \le 6\)
+14903 Find the number of integers x satisfying \(\sqrt[3]{24 + x} + \sqrt{12 - x} \le 6 \)
Hello Guest!
\(\sqrt[3]{24 + x} + \sqrt{12 - x} \le 6 \)
216 192 36 -24 6
125 101 25 -13 5
64 40 16 -4 4
8 -16 9 -3 3
1 -23 4 8 2
0 -24 1 11 1
0 12 0
\(\sqrt[3]{24 + x} + \sqrt{12 - x} \le 6 \)
\(\large x=-24\)
\(\sqrt[3]{24 +(-24)} + \sqrt{12 - (-24)} \le 6\\ \sqrt[3]{0} + \sqrt{36} \le 6 \)
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