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Find the equation of a line perpedicular to the line y=-3x+2 and passes through the point (6,8)

 Mar 13, 2020
 #1
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By definition, if a line is perpendicular to another line, the slopes are the negative reciprocals of each other. As such, the slope of the line you are trying to find is 1/3. Then we know it takes the form y = 1/3x + b. Since it passes through the point (6,8), we can plug in those respective x's and y's, which gives us 8 = 1/3 * 6 + b. This reduces to 8 = 2 + b, so b = 6

 

We then get the line y = 1/3x + 6

 Mar 13, 2020
 #2
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y=-3x+2     this is of the form   y = mx + b     m is slope    = -3   perpindicular is    -1/ -3 = 1/3

 

y = 1/3 x + b     sub in the given point to find 'b'

8 = 1/3 (6) + b     b = 6

 

y = 1/3 x + 6

 Mar 13, 2020

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