Find the equation of a line perpedicular to the line y=-3x+2 and passes through the point (6,8)
By definition, if a line is perpendicular to another line, the slopes are the negative reciprocals of each other. As such, the slope of the line you are trying to find is 1/3. Then we know it takes the form y = 1/3x + b. Since it passes through the point (6,8), we can plug in those respective x's and y's, which gives us 8 = 1/3 * 6 + b. This reduces to 8 = 2 + b, so b = 6
We then get the line y = 1/3x + 6
+36916 y=-3x+2 this is of the form y = mx + b m is slope = -3 perpindicular is -1/ -3 = 1/3
y = 1/3 x + b sub in the given point to find 'b'
8 = 1/3 (6) + b b = 6
y = 1/3 x + 6
