please help!

Part A: Net B

Part B: AB: 3, BC: 5, CD: 5

Part C: 3*4+5(3+4+5)=12+5(12)=12+60=72.

Part B     CD = 8.6 in

Part C     triangle ends (two of them)       two x  1/2 x 3 x 4 in^2

               Back rectangle   3 x 8.6   in^2

               Bottom    4 x 8.6 in^2

               Slanted rectangle   5 x 8.6 in^2

 Add the REDs = ......... in²