What value or values for "c" can make x(squared) +12x+c have one and only one solution?

Guest Jun 8, 2017

#1**+1 **

If you complete the square of x^{2} + 12x + c, you get the value of c to be 36; this gives the value of c for which there will be only one solution. [ x^{2} + 12x + 36 = 0 has only one solution. ]

To complete the square (providing that the coefficient of the squared term is 1), divide the coefficient of the linear term (in this case, this is 12) by 2, and square that result: 12 / 2 = 6 ---> 6^{2} = 36

geno3141
Jun 8, 2017

#1**+1 **

Best Answer

If you complete the square of x^{2} + 12x + c, you get the value of c to be 36; this gives the value of c for which there will be only one solution. [ x^{2} + 12x + 36 = 0 has only one solution. ]

To complete the square (providing that the coefficient of the squared term is 1), divide the coefficient of the linear term (in this case, this is 12) by 2, and square that result: 12 / 2 = 6 ---> 6^{2} = 36

geno3141
Jun 8, 2017