Given that $\triangle+q=59$ and $(\triangle+q)+q=106$, what is the value of $\triangle$?
Δ + q = 59
(Δ + q) + q = 106
(59) + q = 106
q = 106 - 59 = 47
So
Δ + 47 = 59
Δ = 59 - 47 = 12
