\(2z + 3\overline{z} = - 25 - 2i\)
Let z = a + bi
Conjugate z = a - bi
So we have
2 (a + bi) + 3 (a - bi) = -25 - 2i simplify
5a - bi = -25 - 2i
Equate real and non-real terms
5a = -25 -bi = -2i
a = -5 b = 2
So
z = -5 + 2i
