Frank wants to mix 8 L of 4% KCI solution with some 70% KCI to get 50% KCI solution how much 70% solution needs to be used
+128408 Let the unknown amount of the 70% solution be = x
And we have that
8 * 4% + x * 70% = (8 + x) * 50% ......so....
8 * .04 + x * .7 = (8 + x) .5 simplify
.32 + .7x = 4 + .5x subtract .32, .5x from both sides
.2x = 3.68 divide both sides by .2
x = 18.4 KCl of the 70% solution
