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Frank wants to mix 8 L of 4% KCI solution with some 70% KCI to get 50% KCI solution how much 70% solution needs to be used

 Feb 5, 2020
 #1
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Let the unknown amount of the 70% solution  be  =  x

 

And we have that

 

8 * 4%    +   x * 70%    =   (8 + x) * 50%       ......so....

 

 

8 * .04   +  x * .7   =  (8 + x) .5     simplify

 

.32  + .7x  =  4 + .5x         subtract .32, .5x  from both sides

 

.2x  = 3.68         divide both sides by .2

 

x  = 18.4 KCl  of the 70% solution

 

 

cool cool cool

 Feb 5, 2020

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