Real number x and y satisfy
x+(xy^2)=250y, x- (xy^2)= -240y.
Enter all possible values of x, separated by commas.
\(x + xy^2 = 250y\)
\(x - xy^2 = -240y\)
\(2xy^2 = 490y\)
\(xy = 245\)
\(x + 60025 = 250y\)
\(x - 60025 = -240y\)
\(120050 = 490y\)
\(y = 245\)
x = 1, 1225
