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Solve \(x^2+\dfrac{5}{x-3}= 9+\dfrac{5}{x-3}\)

 Jul 4, 2020
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x2 + 5 / (x - 3)  =  9 + 5 / (x - 3)

 

First:  note that x cannot = 3.

 

Subtract  5 / (x - 3)  from both sides:  x2  =  9 

--->  Either  x = 3  or  x = -3  (but x cannot = 3)

--->   x = -3

 Jul 4, 2020

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