Solve \(x^2+\dfrac{5}{x-3}= 9+\dfrac{5}{x-3}\)
x2 + 5 / (x - 3) = 9 + 5 / (x - 3)
First: note that x cannot = 3.
Subtract 5 / (x - 3) from both sides: x2 = 9
---> Either x = 3 or x = -3 (but x cannot = 3)
---> x = -3
